Algorithm
Problem Name: beecrowd | 2764
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/2764
Date Input and Output
By Roberto A. Costa Jr, UNIFEI 
Brazil
Timelimit: 1
Your teacher would like to make a program with the following characteristics:
- Read a date in the DD/MM/YY format;
- Print the date in MM/DD/YY format;
- Print the date in the YY/MM/DD format ;
- Print the date in DD-MM-YY format.
Input
The input consists of several test files. In each test file there is one line. The line has the following DD/MM/YY format where DD, MM and YY are integers. As shown in the following input example.
Output
For each file in the entry, you have an output file. The output file has three lines according to procedures 2, 3, and 4. As shown in the following output example.
| Input Samples | Output Samples |
|
02/08/10 |
08/02/10 10/08/02 02-08-10 |
|
29/07/03 |
07/29/03 03/07/29 29-07-03 |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void)
{
int d, m, y;
while (scanf("%d/%d/%d", &d, &m, &y) != EOF)
{
printf("%02d/%02d/%02d\n", m, d, y);
printf("%02d/%02d/%02d\n", y, m, d);
printf("%02d-%02d-%02d\n", d, m, y);
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main()
{
int dd , mm , yy;
scanf("%d/%d/%d" , &dd , &mm , &yy);
if(mm <10)
cout << "0";
cout << mm << "/";
if(dd < 10)
cout << "0";
cout << dd << "/";
if(yy < 10)
cout << "0";
cout << yy << endl;
if(yy < 10)
cout << "0";
cout << yy << "/";
if(mm < 10)
cout << "0";
cout << mm << "/";
if(dd < 10)
cout << "0";
cout << dd << endl;
if(dd < 10)
cout << "0";
cout << dd << "-";
if(mm < 10)
cout << "0";
cout << mm << "-";
if(yy < 10>
cout << "0";
cout << yy << endl;
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
import java.util.Locale;
public class Main {
public static void main(String[] args) {
Locale.setDefault(new Locale("en", "US"));
Scanner sc = new Scanner(System.in);
//DD/MM/AA
String[] data = new String[4];
data = sc.nextLine().split("/");
System.out.printf("%s/%s/%s\n",data[1],data[0],data[2]);
System.out.printf("%s/%s/%s\n",data[2],data[1],data[0]);
System.out.printf("%s-%s-%s\n",data[0],data[1],data[2]);
sc.close();
}
}
Input
Output
#4 Code Example with Javascript Programming
Code -
Javascript Programming
var input = require('fs').readFileSync('/dev/stdin', 'utf8');
var lines = input.split('\n');
var prompt = function(texto) { return lines.shift();};
var a = prompt().split('/')
const dd = a[0];
const mm = a[1];
const aa = a[2];
console.log(`${mm}/${dd}/${aa}`)
console.log(`${aa}/${mm}/${dd}`)
console.log(`${dd}-${mm}-${aa}`)
Input
Output
#5 Code Example with Python Programming
Code -
Python Programming
while True:
try:
c = input()
c = c.split('/')
x = c[0]
print('%s/%s/%s' %(c[1], c[0], c[2]))
print('%s/%s/%s' %(c[2], c[1], c[0]))
print('%s-%s-%s' %(c[0], c[1], c[2]))
except EOFError:
break
Input
Output