Algorithm


Problem Name: beecrowd | 3303

Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/3303

Big Word

 

By Abner Samuel P. Palmeira, Instituto Federal do Sul de Minas Gerais BR Brazil

Timelimit: 1

Recently Juquinha learned to say big words. These Brazilian Portuguese words are commonly called "palavrao"s. Amazed at the discovery of the boy, her mother forbade him to say any "palavrao", about the risk of the boy losing his allowance.

As Juquinha hates being without an allowance, he hired you to develop a program to tell him if a word is a "palavrao" or not.

"Palavrao"s are words that contain ten or more characters, all other words are considered "palavrinha"s.

 

Input

 

Input consists of several test cases. Each case contains a string that describes the word that Juquinha wants to look up. This string is made up of only lowercase letters and its length does not exceed 20 characters.

 

Output

 

For each test case, print whether the word Juquinha consulted is a "palavrao" (big word) or a "palavrinha" (other words).

 

 

 

Input Samples Output Samples

paralelepipedo

palavrao

 

 

 

carro

palavrinha

 

Code Examples

#1 Code Example with C Programming

Code - C Programming


#include <stdio.h>
#include <string.h>
int main() {

    char a[20];
    scanf("%s", &a);
    if(strlen(a) >= 10){
        printf("palavrao\n");
    }else{
        printf("palavrinha\n");
    }
}

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Input

x
+
cmd
paralelepipedo

Output

x
+
cmd
palavrao

#2 Code Example with C++ Programming

Code - C++ Programming


#include <iostream>
 
using namespace std;
 
int main() {
 
    string palavra;
    cin >> palavra;
    if(palavra.length() >= 10){
        cout << "palavrao\n";
    }else{
        cout << "palavrinha\n";
    }
}

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Input

x
+
cmd
paralelepipedo

Output

x
+
cmd
palavrao

#3 Code Example with Javascript Programming

Code - Javascript Programming


const { readFileSync } = require("fs")
const [word] = readFileSync("/dev/stdin", "utf8").split("\n")

const getWordType = (str = "") => str.length >= 10 ? "palavrao" : "palavrinha"

console.log(getWordType(word))
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Input

x
+
cmd
paralelepipedo

Output

x
+
cmd
palavrao

#4 Code Example with Javascript Programming

Code - Javascript Programming


var input = require('fs').readFileSync('/dev/stdin', 'utf8');
var lines = input.split('\n');
if(lines[0].length >= 10) {
  console.log('palavrao')
} else {
  console.log('palavrinha')
}
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Input

x
+
cmd
paralelepipedo

Output

x
+
cmd
palavrao

#5 Code Example with Python Programming

Code - Python Programming


x = input()
print("palavrao") if len(x)>=10 else print("palavrinha")

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Input

x
+
cmd
paralelepipedo

Output

x
+
cmd
palavrao
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Demonstration


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