Algorithm
Problem Name: beecrowd | 2547
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/2547
Roller Coaster
By Flávio Zavan, UFPR 
Brazil
Timelimit: 1
Everyone in Nlogônia is really excited with the opening of Ricardo Barreiro World, the newest amusement park in the country. Its roller coaster, the fastest in the continent, is being widely advertised on TV and Radio. It’s the attraction everyone, from kids to grandmas, wants to ride.
Unfortunately, some restrictions were imposed by the government during the attraction’s homologation. For safety reasons, there is a minimum and a maximum height people must have to ride the roller coaster.
In the inauguration day, every guest filled a register in which they indicated their heights. In order to reduce lines and optimize the operation, you were hired to write a program that, given the number of guests, the minimum and maximum allowed height, and the height of every guest, determine how many guests are allowed to ride the roller coaster.
Input
The input contains several test cases. The first line of each test case contains three integers N (1 ≤ N ≤ 100), Amin and Amax (50 ≤ Amin ≤ Amax ≤ 250), the number of guests, the minimum and the maximum allowed height, respectively, in centimeters.
Each of the next N lines contains an integer (50 ≤ Ai ≤ 250), the height of the i-th guest, in centimeters.
The input ends with end-of-file (EOF).
Output
For each test case, print a single line containing the number of guests allowed to ride the roller coaster.
| Input Sample | Output Sample |
|
8 160 182 |
5 |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void)
{
int a, b, i, n, count;
while (scanf("%i %i %i", &n, &a, &b) != EOF)
{
int arr[n];
count=0;
for (i = 0; i < n; ++i)
scanf("%i", &arr[i]);
for (i = 0; i < n; ++i)
{
if (arr[i] >= a && arr[i] <= b)
++count;
}
printf("%i\n", count);
}
return 0;
}
Input
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <cstdio>
#include <iostream>
using namespace std;
int main(){
int n, n1, amin, amax, permited = 0;
while(cin >> n >> amin >> amax){
while(n--){
cin >> n1;
if (n1 >= amin and n1 < = amax) {
permited ++;
}
}
cout << permited << endl;
permited = 0;
}
return 0;
}
Input
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while(sc.hasNext()) {
int n, min, max, altura, conta=0;
n = sc.nextInt();
min = sc.nextInt();
max = sc.nextInt();
for (int x = 0 ; x < n ; x++) {
altura = sc.nextInt();
if (altura >= min && altura >= 50 && altura < = max && altura <= 250 && min <= max && min >= 50 && max <= 250)
conta++;
}
System.out.println(conta);
}
sc.close();
}
}
Input
Output
#4 Code Example with Javascript Programming
Code -
Javascript Programming
const { createReadStream } = require("node:fs")
const { createInterface } = require("node:readline")
class LineReader {
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
* @return {import("node:readline").ReadLine}
*/
static createReadLineInterface(path, encoding = "utf8") {
const readStreamOptions = {
encoding: encoding,
flags: "r",
emitClose: true,
autoClose: true
}
return createInterface({
input: createReadStream(path, readStreamOptions),
crlfDelay: Infinity,
terminal: false
})
}
/**
* @param {import("node:fs").PathLike} path
* @param {BufferEncoding} encoding
*/
static create(path, encoding) {
const RLI = LineReader.createReadLineInterface(path, encoding)
let EOF = false
const nextLineGenerator = (async function* () {
for await (const line of RLI)
yield line
})()
RLI.once("close", () => { EOF = true })
return {
hasNextLine: () => !EOF,
nextLine: async (/** @type {unknown} */ fn) => {
const { value } = (await nextLineGenerator.next())
return (typeof fn === "function") ? fn(value) : value
},
close: () => RLI.close()
}
}
}
async function main() {
const output = []
const PATH = "/dev/stdin"
const ENCODING = "utf8"
const lineReader = LineReader.create(PATH, ENCODING)
while (lineReader.hasNextLine()) {
const line = await lineReader.nextLine()
if (Boolean(line) === false) break // EOFile Condition
let countAvailableVisitors = 0
const [N, min, max] = line
.split(" ", 3)
.map(value => Number.parseInt(value, 10))
for (let index = 0; index < N; index += 1) {
const visitorHeight = Number.parseInt(await lineReader.nextLine(), 10)
if (min <= visitorHeight && visitorHeight <= max) countAvailableVisitors += 1
}
output.push(countAvailableVisitors)
}
if (lineReader.hasNextLine()) lineReader.close()
console.log(output.join("\n"))
}
main()
Input
Output
#5 Code Example with Python Programming
Code -
Python Programming
while True:
try:
n, amin, amax = [int(x) for x in input().split()]
t = 0
while n:
n -= 1
i = int(input())
if i >= amin and i <= amax:
t += 1
print(t)
except EOFError:
break
Input
Output