## Algorithm

Problem Name: beecrowd | 2313

# Which Triangle

By Alexandre A. Melo, IFSC Brazil

Timelimit: 1

Given three values, find out if they form a triangle. If so, check if the triangle is scalene, isoceles or equilateral and if it is a triangle rectangle or not.

## Input

Input is given by three integers A,B e C (0 < A,B,C < 105).

## Output

The output must be the one single line containing the string "Invalido" if the input values do not represent a triangle.

If the values can be the sides of a triangle the output must be "Valido-Equilatero" if such triangle is equilateral, "Valido-Escaleno" if it is scalene or "Valido-Isoceles" if it is isoceles. The next line of output must read "Retangulo: S" if the triangle is rectangle or "Retangulo: N" otherwise, as shown in the examples.

 Input Samples Output Samples 4 6 2 Invalido

 4 3 3 Valido-Isoceles Retangulo: N

 3 4 5 Valido-Escaleno Retangulo: S

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>

int main(void)

{
int i, j, a[3], temp;

for (i = 0; i  <  3; ++i)
scanf("%i", &a[i]);

for (i = 0; i  <  3-1; ++i)
{
for (j = i+1; j  <  3; ++j)
{
if (a[j] < a[i])
{
temp = a[i];
a[i] = a[j];
a[j] = temp;
}
}
}

if (a[2] >= a[0]+a[1])
printf("Invalido\n");

else
{
if (a[0] == a[1] && a[1] == a[2])
printf("Valido-Equilatero\n");

else if (a[0] != a[1] && a[0] != a[2] && a[1] != a[2])
printf("Valido-Escaleno\n");

else
printf("Valido-Isoceles\n");

if (a[2]*a[2] == (a[0]*a[0]+a[1]*a[1]))
printf("Retangulo: S\n");

else
printf("Retangulo: N\n");
}

return 0;
}
``````
Copy The Code &

Input

cmd
4 6 2

Output

cmd
Invalido

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include<bits/stdc++.h>
using namespace std;

int main()
{
int a,b,c;
string ans = "" ;
cin >> a >> b >> c ;
if(a+c > b){
if((a != b and b == c) or ( a == c and a != b) or ( a == b and c != b))
ans = "Valido-Isoceles";
else if(a == b and a == c)
ans = "Valido-Equilatero" ;
else if(a != b and b != c and a != c)
ans = "Valido-Escaleno";
}
else{
ans = "Invalido";
}

if(ans != "Invalido"){
if(pow(a,2) == pow(b,2) + pow(c,2) or pow(b,2) == pow(a,2) + pow(c,2) or pow(c,2) == pow(a,2) + pow(b,2))
cout << ans << endl << "Retangulo: S" << endl ;
else
cout << ans << endl << "Retangulo: N" << endl;
}
else
cout << ans << endl;

return 0;
}
``````
Copy The Code &

Input

cmd
4 6 2

Output

cmd
Invalido

### #3 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
var lines = input.split('\n');
const numbers = lines.shift().split(" ");
numbers.sort((a,b) => a - b).reverse();

const [a, b, c] = numbers
const A = parseFloat(a);
const B = parseFloat(b);
const C = parseFloat(c);

if(A >= B + C){
console.log("Invalido");
return;
}

if(A == B && B == C){
console.log("Valido-Equilatero");
}
else if(A == B || A == C || B == C){
console.log("Valido-Isoceles");
}

else if(A != B && B != C && C != A){
console.log("Valido-Escaleno");
}

if(Math.pow(A, 2) == (Math.pow(B,2) + Math.pow(C,2))){
console.log("Retangulo: S");
}
else{
console.log("Retangulo: N");
}

``````
Copy The Code &

Input

cmd
4 6 2

Output

cmd
Invalido

### #4 Code Example with Python Programming

```Code - Python Programming```

``````
A, B, C = input().split()

A = int(A)
B = int(B)
C = int(C)

if(A < B and A < C and B < C):

a = C
b = B
c = A

elif(A < B and A < C and C < B):

a = B
b = C
c = A

elif(B < A and B < C and A < C):

a = C
b = A
c = B

elif(B < A and B < C and C < A):

a = A
b = C
c = B

elif(C < A and C < B and A < B):

a = B
b = A
c = C

elif(C < A and C < B and B < A):

a = A
b = B
c = C

elif(A == B and A < C):

a = C
b = A
c = A

elif(A == B and C < A):

a = A
b = A
c = C

elif(A == C and A < B):

a = B
b = A
c = A

elif(A == C and B < A):

a = A
b = B
c = A

elif(B == C and B < A):

a = A
b = B
c = B

elif(B == C and A < B>:

a = B
b = A
c = B

else:

a = A
b = B
c = C

if(a >= b + c):

print("Invalido")

exit()

elif(a == b and b == c):

print("Valido-Equilatero")

elif(a == b or a == c or b == c):

print("Valido-Isoceles")

else:

print("Valido-Escaleno")

if(((a * a) == b * b + c * c) == True):

print("Retangulo: S")

else:

print("Retangulo: N")
``````
Copy The Code &

Input

cmd
4 6 2

Output

cmd
Invalido