Algorithm
Problem Name: 2 AD-HOC - beecrowd | 1794 | [PJ]
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/1794
Laundry
By Cristhian Bonilha, UTFPR 
Brazil
Timelimit: 1
Tired of washing your dirty clothes, your mother decided that, for now on, who washes your clothes is you.
On the laundry room of your home there is a washer and a dryer, each with its own limits of minimum and maximum amount of clothes to be washed and dried per time. Therefore, the washer can only be used if you put at least LA and at most LB clothes inside it, and similarly the dryer can only be used if you put at least SA and at most SB clothes inside it.
You currently have N clothes to be washed and dried, and you want to find out if it is possible to use the washer and dryer to wash and dry all of your clothes, following the rules described above.
Input
On the first line of input there is an integer N (1 ≤ N ≤ 100).
On the second line of input there are two integers LA and LB (1 ≤ LA < LB ≤ 100).
On the third line of input there are two integers SA and SB (1 ≤ SA < SB ≤ 100).
Output
Print the word "possivel" if it is possible to wash and dry all of your clothes following the rules described on the statement, or "impossivel" otherwise.
| Input Samples | Output Samples |
|
10 |
possivel |
|
12 |
impossivel |
|
20 |
possivel |
Code Examples
#1 Code Example with C Programming
Code -
C Programming
#include <stdio.h>
int main(void) {
int n, la, lb;
scanf("%d", &n);
scanf("%d %d", &la, &lb);
if (la < = n && n <= lb) {
scanf("%d %d", &la, &lb);
if (la <= n && n <= lb)
printf("possivel");
else printf("impossivel");
}
else {
scanf("%d %d", &la, &lb);
printf("impossivel");
}
printf("\n");
return 0;
}
Input
8 12
10 14
Output
#2 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
using namespace std;
int main(void) {
int n, la, lb;
cin >> n;
cin >> la >> lb;
if (la < = n and n <= lb) {
cin >> la >> lb;
if (la < = n and n <= lb)
cout << "possivel";
else cout << "impossivel";
}
else {
cin >> la >> lb;
cout << "impossivel";
}
cout << endl;
return 0;
}
Input
8 12
10 14
Output
#3 Code Example with Java Programming
Code -
Java Programming
import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.Closeable;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import java.io.PrintWriter;
import java.util.StringTokenizer;
public class Main {
static Reader in = new Reader(System.in);
static Writer out = new Writer(System.out);
public static void main(String[] args) throws IOException {
int N = in.nextInt();
int LA = in.nextInt();
int LB = in.nextInt();
int SA = in.nextInt();
int SB = in.nextInt();
boolean f = LA < = N && N <= LB && SA <= N && N <= SB;
out.println(f ? "possivel": "impossivel" );
in.close();
out.flush();
out.close();
}
static class Reader implements Closeable {
private final BufferedReader reader;
private StringTokenizer tokenizer;
public Reader(InputStream input) {
reader = new BufferedReader(
new InputStreamReader(input));
tokenizer = new StringTokenizer("");
}
private StringTokenizer getTokenizer() throws IOException {
if (tokenizer == null || !tokenizer.hasMoreTokens()) {
String line = nextLine();
if (line == null) {
return null;
}
tokenizer = new StringTokenizer(line);
}
return tokenizer;
}
public boolean hasNext() throws IOException {
return getTokenizer() != null;
}
public String next() throws IOException {
return hasNext() ? tokenizer.nextToken() : null;
}
public String nextLine() throws IOException {
tokenizer = null;
return reader.readLine();
}
public int nextInt() throws IOException {
return Integer.parseInt(next());
}
public long nextLong() throws IOException {
return Long.parseLong(next());
}
public float nextFloat() throws IOException {
return Float.parseFloat(next());
}
public double nextDouble() throws IOException {
return Double.parseDouble(next());
}
public String[] nextStringArray(int size) throws IOException {
String[] array = new String[size];
for (int i = 0; i < size; i++) {
array[i] = next();
}
return array;
}
public int[] nextIntArray(int size) throws IOException {
int[] array = new int[size];
for (int i = 0; i < size; i++) {
array[i] = nextInt();
}
return array;
}
public long[] nextLongArray(int size) throws IOException {
long[] array = new long[size];
for (int i = 0; i < size; i++) {
array[i] = nextLong();
}
return array;
}
public double[] nextDoubleArray(int size) throws IOException {
double[] array = new double[size];
for (int i = 0; i < size; i++) {
array[i] = nextDouble();
}
return array;
}
@Override
public void close() throws IOException {
tokenizer = null;
reader.close();
}
}
static class Writer {
private final PrintWriter writer;
public Writer(OutputStream outputStream) {
writer = new PrintWriter(new BufferedWriter(new OutputStreamWriter(outputStream)));
}
public void print(Object... objects) {
for (int i = 0; i < objects.length; i++) {
if (i != 0) {
writer.print(' ');
}
writer.print(objects[i]);
}
}
public void println(Object... objects) {
print(objects);
writer.println();
}
public void close() {
writer.close();
}
public void flush() {
writer.flush();
}
}
}
Input
8 12
10 14
Output
#4 Code Example with Javascript Programming
Code -
Javascript Programming
const { readFileSync } = require("node:fs")
const [N, LA, LB, SA, SB] = readFileSync("/dev/stdin", "utf8")
.split(/\s+/, 5)
.map((value) => Number.parseInt(value, 10))
console.log(
N >= Math.max(LA, SA) && N <= Math.min(LB, SB) ? "possivel" : "impossivel"
)
Input
8 12
10 14
Output
#5 Code Example with Python Programming
Code -
Python Programming
n = int(input())
e = str(input()).split()
la = int(e[0])
lb = int(e[1])
if la <= n <= lb:
e = str(input()).split()
la = int(e[0])
lb = int(e[1])
if la <= n <= lb: print('possivel')
else: print('impossivel')
else:
input()
print('impossivel')
Input
8 12
10 14
Output