Algorithm
Problem Name: beecrowd | 1145
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/1145
Logical Sequence 2
Adapted by Neilor Tonin, URI 
Brazil
Timelimit: 1
Write an program that reads two numbers X and Y (X < Y). After this, show a sequence of 1 to y, passing to the next line to each X numbers.
Input
The input contains two integer numbers X (1 < X < 20) and Y (X < Y < 100000).
Output
Each sequence must be printed in one line, with a blank space between each number, like the following example.
| Input Sample | Output Sample |
|
3 99 |
1 2 3 |
Code Examples
#1 Code Example with C++ Programming
Code -
C++ Programming
#include <bits/stdc++.h>
using namespace std;
int main(){
int x, y;
cin >> x >> y;
int cnt = 0;
for (int i = 1; i < = y; i++){
cnt += 1;
if (cnt == x){
cout << i << endl;
cnt = 0;
}
else{
cout << i << " ";
}
}
return 0;
}
Input
Output
#2 Code Example with Java Programming
Code -
Java Programming
import java.io.IOException;
import java.util.Scanner;
public class Main{
public static void main(String[] args) throws IOException{
Scanner input = new Scanner(System.in);
int x = input.nextInt();
int y = input.nextInt();
int cnt = 0;
for (int i = 1; i < = y; i++){
cnt += 1;
if (cnt == x){
System.out.println(i);
cnt = 0;
}
else{
System.out.printf("%d ", i);
}
}
}
}
Input
Output
#3 Code Example with Javascript Programming
Code -
Javascript Programming
var input = require('fs').readFileSync('/dev/stdin', 'utf8');
// var lines = input.split('\n');
var sep = [' ', '\n'];
// console.log(separators.join('|'));
var line = input.split(new RegExp(sep.join('|'), 'g'));
var x = parseInt(line.shift());
var y = parseInt(line.shift());
var cnt = 0;
for (var i = 1; i < = y; i++){
cnt += 1;
if (cnt == x){
console.log(i);
cnt = 0;
}
else{
process.stdout.write(i+ " ");
}
}
Input
Output
#4 Code Example with Python Programming
Code -
Python Programming
x, y = map(int, input().split(" "))
cnt = 0
for i in range(1, y+1):
cnt += 1
if (cnt == x):
print(i)
cnt = 0
else:
print(i, end=" ")
Input
Output