Algorithm
Problem Name: beecrowd | 1174
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/1174
Array Selection I
Adapted by Neilor Tonin, URI 
Brazil
Timelimit: 1
In this problem, your task is to read an array A[100]. At the end, print all array positions that store a number less or equal to 10 and the number stored in that position.
Input
The input contains 100 numbers. Each number can be integer, floating-point number, positive or negative.
Output
For each number of the array that is equal to 10 or less, print "A [i] = x", where i is the position of the array and x is the number stored in the position, with one digit after the decimal point.
| Input Sample | Output Sample |
|
0 |
A[0] = 0.0 |
Code Examples
#1 Code Example with C++ Programming
Code -
C++ Programming
#include <iostream>
#include <iomanip>
using namespace std;
int main(){
double lista[100];
double k;
for(int i = 0; i < 100; i++){
cin >> k;
lista[i] = k;
}
for(int i = 0; i < 100; i++){
if(lista[i] <= 10){
cout << fixed << setprecision(1>;
cout << "A[" << i << "] = " << lista[i] << "\n";
}
}
}
Input
Output
#2 Code Example with Javascript Programming
Code -
Javascript Programming
const input = require('fs').readFileSync('/dev/stdin', 'utf8');
const lines = input.split('\n');
let lista = [];
for(var i = 0; i < 100; i++){
let o = parseFloat(lines.shift());
lista.push(o);
}
for(var i = 0; i < 100; i++){
if(lista[i] <= 10){
console.log(`A[${i}] = ${(lista[i]).toFixed(1)}`>;
}
}
Input
Output
#3 Code Example with Python Programming
Code -
Python Programming
lista = []
for i in range(0, 100):
lista+=[float(input())]
for i in range(0, 100):
if lista[i] <= 10:
print(f'A[{i}] = {lista[i]:.1f}')
Input
Output