## Algorithm

Problem Name: beecrowd | 1073
Problem Link: https://www.beecrowd.com.br/judge/en/problems/view/1073

# Even Square

Adapted by Neilor Tonin, URI Brazil

Timelimit: 1

Read an integer N. Print the square of each one of the even values from 1 to N including N if it is the case.

## Input

The input contains an integer N (5 < N < 2000).

## Output

Print the square of each one of the even values from 1 to N, as the given example.

Be carefull! Some language automaticly print 1e+006 instead 1000000. Please configure your program to print the correct format setting the output precision.

 Input Sample Output Sample 6 2^2 = 4 4^2 = 16 6^2 = 36

## Code Examples

### #1 Code Example with C Programming

```Code - C Programming```

``````
#include <stdio.h>
int main()
{
int n, i;

scanf("%d", &n);

for ( i = 1; i  < = n; ++i)
{
if(i % 2 == 0){
printf("%d^2 = %dn", i,(i * i));
}
}

return 0;
}
``````
Copy The Code &

Input

cmd
6

Output

cmd
2^2 = 4 4^2 = 16 6^2 = 36

### #2 Code Example with C++ Programming

```Code - C++ Programming```

``````
#include <iostream>
using namespace std;

int main(int argc, const char * argv[])
{
int N, i;

cin >> N;

for(i = 1; i  < = N; i++) {
if(i%2 == 0) {
cout << i << "^2 = " << i*i << endl;
}
}

return 0;
}
``````
Copy The Code &

Input

cmd
6

Output

cmd
2^2 = 4 4^2 = 16 6^2 = 36

### #3 Code Example with Java Programming

```Code - Java Programming```

``````
import java.util.Scanner;
import java.io.IOException;

public class Main {

public static void main(String[] args) {
int N;
Scanner input =new Scanner(System.in);
N =input.nextInt();

for (int i = 2; i  < = N; i+= 2) {
System.out.print(i+"^2 = "+(i*i)+"n");
}
}
}
``````
Copy The Code &

Input

cmd
6

Output

cmd
2^2 = 4 4^2 = 16 6^2 = 36

### #4 Code Example with Python Programming

```Code - Python Programming```

``````
a=int(input())
for n in range(1,(a+1)):
if (n%2==0):
print("%d^2 = %d" %(n, n**2))
``````
Copy The Code &

Input

cmd
6

Output

cmd
2^2 = 4 4^2 = 16 6^2 = 36
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