Algorithm


Problem Name: 1041. Robot Bounded In Circle

On an infinite plane, a robot initially stands at (0, 0) and faces north. Note that:

  • The north direction is the positive direction of the y-axis.
  • The south direction is the negative direction of the y-axis.
  • The east direction is the positive direction of the x-axis.
  • The west direction is the negative direction of the x-axis.

The robot can receive one of three instructions:

  • "G": go straight 1 unit.
  • "L": turn 90 degrees to the left (i.e., anti-clockwise direction).
  • "R": turn 90 degrees to the right (i.e., clockwise direction).

The robot performs the instructions given in order, and repeats them forever.

Return true if and only if there exists a circle in the plane such that the robot never leaves the circle.

 

Example 1:

Input: instructions = "GGLLGG"
Output: true
Explanation: The robot is initially at (0, 0) facing the north direction.
"G": move one step. Position: (0, 1). Direction: North.
"G": move one step. Position: (0, 2). Direction: North.
"L": turn 90 degrees anti-clockwise. Position: (0, 2). Direction: West.
"L": turn 90 degrees anti-clockwise. Position: (0, 2). Direction: South.
"G": move one step. Position: (0, 1). Direction: South.
"G": move one step. Position: (0, 0). Direction: South.
Repeating the instructions, the robot goes into the cycle: (0, 0) --> (0, 1) --> (0, 2) --> (0, 1) --> (0, 0).
Based on that, we return true.

Example 2:

Input: instructions = "GG"
Output: false
Explanation: The robot is initially at (0, 0) facing the north direction.
"G": move one step. Position: (0, 1). Direction: North.
"G": move one step. Position: (0, 2). Direction: North.
Repeating the instructions, keeps advancing in the north direction and does not go into cycles.
Based on that, we return false.

Example 3:

Input: instructions = "GL"
Output: true
Explanation: The robot is initially at (0, 0) facing the north direction.
"G": move one step. Position: (0, 1). Direction: North.
"L": turn 90 degrees anti-clockwise. Position: (0, 1). Direction: West.
"G": move one step. Position: (-1, 1). Direction: West.
"L": turn 90 degrees anti-clockwise. Position: (-1, 1). Direction: South.
"G": move one step. Position: (-1, 0). Direction: South.
"L": turn 90 degrees anti-clockwise. Position: (-1, 0). Direction: East.
"G": move one step. Position: (0, 0). Direction: East.
"L": turn 90 degrees anti-clockwise. Position: (0, 0). Direction: North.
Repeating the instructions, the robot goes into the cycle: (0, 0) --> (0, 1) --> (-1, 1) --> (-1, 0) --> (0, 0).
Based on that, we return true.

 

Constraints:

  • 1 <= instructions.length <= 100
  • instructions[i] is 'G', 'L' or, 'R'.

Code Examples

#1 Code Example with Java Programming

Code - Java Programming


class Solution {
  public boolean isRobotBounded(String instructions) {
    int[][] directions = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}};
    int x = 0;
    int y = 0;
    int idx = 0;
    for (char c : instructions.toCharArray()) {
      if (c == 'L') {
        idx = (idx + 3) % 4;
      }
      else if (c == 'R') {
        idx = (idx + 1) % 4;
      }
      else {
        x += directions[idx][0];
        y += directions[idx][1];
      }
    }
    return (x == 0 && y == 0) || idx != 0;
  }
}
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Input

x
+
cmd
instructions = "GGLLGG"

Output

x
+
cmd
true

#2 Code Example with Javascript Programming

Code - Javascript Programming


const isRobotBounded = function(instructions) {
  let x = 0, y = 0, i = 0, d = [[0, 1], [1, 0], [0, -1], [ -1, 0]];
  for (let j = 0; j  <  instructions.length; ++j)
    if (instructions.charAt(j) === 'R') i = (i + 1) % 4;
    else if (instructions .charAt(j) === 'L') i = (i + 3) % 4;
    else {
        x += d[i][0]; y += d[i][1];
    }
  return x == 0 && y == 0 || i > 0;
};
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Input

x
+
cmd
instructions = "GGLLGG"

Output

x
+
cmd
true

#3 Code Example with Python Programming

Code - Python Programming


class Solution:
    def isRobotBounded(self, instructions: str) -> bool:
        x, y, dx, dy = 0, 0, 0, 1
        for _ in range(4):
            for ins in instructions:
                if ins == 'G':
                    x += dx
                    y += dy
                elif ins == 'L':
                    dx, dy = -dy, dx
                else:
                    dx, dy = dy, -dx
        return x == y == 0
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Input

x
+
cmd
instructions = "GG"

Output

x
+
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false

#4 Code Example with C# Programming

Code - C# Programming


namespace LeetCode
{
    public class _1041_RobotBoundedInCircle
    {
        public bool IsRobotBounded(string instructions)
        {
            var directions = new int[4][] { new int[2] { 0, 1 }, new int[2] { 1, 0 }, new int[2] { 0, -1 }, new int[2] { -1, 0 } };
            int x = 0, y = 0, dir = 0;

            foreach (var ch in instructions)
            {
                if (ch == 'L')
                    dir = (dir + 3) % 4;
                else if (ch == 'R')
                    dir = (dir + 1) % 4;
                else
                {
                    x += directions[dir][0];
                    y += directions[dir][1];
                }
            }

            return (x == 0 && y == 0) || (dir != 0);
        }
    }
}
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Input

x
+
cmd
instructions = "GG"

Output

x
+
cmd
false
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