Problem

While Alice was drinking sugarcane juice, she started wondering about the following facts:

• The juicer sells each glass of sugarcane juice for 50 coins.
• He spends 20% of his total income on buying sugarcane.
• He spends 20% of his total income on buying salt and mint leaves.
• He spends 30% of his total income on shop rent.

Alice wonders, what is the juicer's profit (in coins) when he sells  glasses of sugarcane juice?

Input Format

• The first line of input will contain an integer  — the number of test cases. The description of  test cases follows.
• The first and only line of each test case contains an integer , as described in the problem statement.

Output Format

For each test case, output on a new line the juicer's profit when he sells  glasses of juice.

• 1≤�≤1000
• 1≤�≤106

Sample 1:

Input

Output

4
2
4
5
10

30
60
75
150


Explanation:

Test case 1: The total income is 50×2=100 coins. The juicer spends 20 coins on sugarcane, 20 coins on salt and mint leaves and 30 coins on rent. Thus, the profit is 100−(20+20+30)=30 coins.

Test case 2: The total income is 50×4=200 coins. The juicer spends 40 coins on sugarcane, 40 coins on salt and mint leaves and 60 coins on rent. Thus, the profit is 200−(40+40+60)=60 coins.

Test case 3: The total income is 50×5=250 coins. The juicer spends 50 coins on sugarcane, 50 coins on salt and mint leaves and 75 coins on rent. Thus, the profit is 250−(50+50+75)=75 coins.

Test case 4: The total income is 50×10=500 coins. The juicer spends 100 coins on sugarcane, 100 coins on salt and mint leaves and 150 coins on rent. Thus, the profit is 500−(100+100+150)=150 coins.

Code Examples

#1 Code Example with C Programming

Code - C Programming

#include<stdio.h>
int main()
{
scanf("%d",&t);
while(t--)
{
scanf("%d",&n);
profit=n*50-n*50*.2-n*50*.2-n*50*.3;
printf("%d\n",profit);
}
} 
Copy The Code &

Input

cmd
4
2
4
5
10

Output

cmd
30
60
75
150