Algorithm
Problem Name: 722. Remove Comments
Given a C++ program, remove comments from it. The program source is an array of strings source
where source[i]
is the ith
line of the source code. This represents the result of splitting the original source code string by the newline character '\n'
.
In C++, there are two types of comments, line comments, and block comments.
- The string
"//"
denotes a line comment, which represents that it and the rest of the characters to the right of it in the same line should be ignored. - The string
"/*"
denotes a block comment, which represents that all characters until the next (non-overlapping) occurrence of"*/"
should be ignored. (Here, occurrences happen in reading order: line by line from left to right.) To be clear, the string"/*/"
does not yet end the block comment, as the ending would be overlapping the beginning.
The first effective comment takes precedence over others.
- For example, if the string
"//"
occurs in a block comment, it is ignored. - Similarly, if the string
"/*"
occurs in a line or block comment, it is also ignored.
If a certain line of code is empty after removing comments, you must not output that line: each string in the answer list will be non-empty.
There will be no control characters, single quote, or double quote characters.
- For example,
source = "string s = "/* Not a comment. */";"
will not be a test case.
Also, nothing else such as defines or macros will interfere with the comments.
It is guaranteed that every open block comment will eventually be closed, so "/*"
outside of a line or block comment always starts a new comment.
Finally, implicit newline characters can be deleted by block comments. Please see the examples below for details.
After removing the comments from the source code, return the source code in the same format.
Example 1:
Input: source = ["/*Test program */", "int main()", "{ ", " // variable declaration ", "int a, b, c;", "/* This is a test", " multiline ", " comment for ", " testing */", "a = b + c;", "}"] Output: ["int main()","{ "," ","int a, b, c;","a = b + c;","}"] Explanation: The line by line code is visualized as below: /*Test program */ int main() { // variable declaration int a, b, c; /* This is a test multiline comment for testing */ a = b + c; } The string /* denotes a block comment, including line 1 and lines 6-9. The string // denotes line 4 as comments. The line by line output code is visualized as below: int main() { int a, b, c; a = b + c; }
Example 2:
Input: source = ["a/*comment", "line", "more_comment*/b"] Output: ["ab"] Explanation: The original source string is "a/*comment\nline\nmore_comment*/b", where we have bolded the newline characters. After deletion, the implicit newline characters are deleted, leaving the string "ab", which when delimited by newline characters becomes ["ab"].
Constraints:
1 <= source.length <= 100
0 <= source[i].length <= 80
source[i]
consists of printable ASCII characters.- Every open block comment is eventually closed.
- There are no single-quote or double-quote in the input.
Code Examples
#1 Code Example with Java Programming
Code -
Java Programming
class Solution {
public List removeComments(String[] source) {
StringBuilder sb = new StringBuilder();
List < String> list = new ArrayList<>();
boolean blockComment = false;
for (String word : source) {
for (int i = 0; i < word.length(); i++) {
if (!blockComment) {
if ((i + 1) < word.length() && word.charAt(i) == '/' && word.charAt(i + 1) == '/') {
break;
}
else if ((i + 1) < word.length() && word.charAt(i) == '/' && word.charAt(i + 1) == '*') {
blockComment = true;
i++;
}
else {
sb.append(word.charAt(i));
}
}
else {
if ((i + 1) < word.length() && word.charAt(i) == '*' && word.charAt(i + 1) == '/') {
blockComment = false;
i++;
}
}
}
if (!blockComment && sb.length() > 0) {
list.add(sb.toString());
sb.setLength(0);
}
}
return list;
}
}
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#2 Code Example with Javascript Programming
Code -
Javascript Programming
const removeComments = function (source) {
const code = source.join('\n')
const isBlockStart = (c, i) => c[i] === '/' && c[i + 1] === '*'
const isBlockEnd = (c, i) => c[i] === '*' && c[i + 1] === '/'
const isLineStart = (c, i) => c[i] === '/' && c[i + 1] === '/'
const isNewLine = (c, i) => c[i] === '\n'
let i = 0,
output = ''
while (i < code.length) {
if (isBlockStart(code, i)) {
i += 2
while (!isBlockEnd(code, i) && i < code.length) i++
i += 2
} else if (isLineStart(code, i)) {
i += 2
while (!isNewLine(code, i) && i < code.length) i++
} else {
output += code[i++]
}
}
return output.split('\n').filter((l) => l.length)
}
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#3 Code Example with Python Programming
Code -
Python Programming
class Solution:
def removeComments(self, source):
res, block, cont, blockStart = [], False, False, -1
for line in source:
if not cont: cache = ""
for i, c in enumerate(line):
if not block: cache += c
if cache[-2:] == "//":
cache = cache[:-2]
break
elif cache[-2:] == "/*": blockStart, cache, block = i, cache[:-2], True
elif line[i - 1:i + 1] == "*/" and blockStart < i - 1: block = False
if not block:
if cache: res += cache,
cont = False
else: cont, blockStart = True, -1
return res
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#4 Code Example with C# Programming
Code -
C# Programming
using System.Collections.Generic;
using System.Text;
namespace LeetCode
{
public class _0722_RemoveComments
{
public IList < string> RemoveComments(string[] source)
{
var inCommentBlock = false;
var sb = new StringBuilder();
var result = new List < string>();
foreach (var line in source)
{
if (!inCommentBlock && sb.Length > 0) sb.Clear();
for (int i = 0; i < line.Length; i++)
{
if (inCommentBlock)
{
if (i + 1 < line.Length && line[i] == '*' && line[i + 1] == '/')
{
inCommentBlock = false;
i++;
}
continue;
}
if (i + 1 < line.Length)
if (line[i] == '/' && line[i + 1] == '/') break;
else if (line[i] == '/' && line[i + 1] == '*')
{
inCommentBlock = true;
i++;
continue;
}
sb.Append(line[i]);
}
if (!inCommentBlock && sb.Length > 0)
result.Add(sb.ToString());
}
return result;
}
}
}
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