Algorithm
Problem Name: 1090. Largest Values From Labels
Problem Link: https://leetcode.com/problems/largest-values-from-labels/
There is a set of n
items. You are given two integer arrays values
and labels
where the value and the label of the ith
element are values[i]
and labels[i]
respectively. You are also given two integers numWanted
and useLimit
.
Choose a subset s
of the n
elements such that:
- The size of the subset
s
is less than or equal tonumWanted
. - There are at most
useLimit
items with the same label ins
.
The score of a subset is the sum of the values in the subset.
Return the maximum score of a subset s
.
Example 1:
Input: values = [5,4,3,2,1], labels = [1,1,2,2,3], numWanted = 3, useLimit = 1 Output: 9 Explanation: The subset chosen is the first, third, and fifth items.
Example 2:
Input: values = [5,4,3,2,1], labels = [1,3,3,3,2], numWanted = 3, useLimit = 2 Output: 12 Explanation: The subset chosen is the first, second, and third items.
Example 3:
Input: values = [9,8,8,7,6], labels = [0,0,0,1,1], numWanted = 3, useLimit = 1 Output: 16 Explanation: The subset chosen is the first and fourth items.
Constraints:
n == values.length == labels.length
1 <= n <= 2 * 104
0 <= values[i], labels[i] <= 2 * 104
1 <= numWanted, useLimit <= n
Code Examples
#1 Code Example with Javascript Programming
Code -
Javascript Programming
const largestValsFromLabels = function(values, labels, num_wanted, use_limit) {
return Object.entries(
labels.reduce((ret, l, i) => {
ret[l] = (ret[l] || []).concat(values[i])
return ret
}, {})
)
.reduce(
(candi, [k, vals]) =>
candi.concat(vals.sort((a, b) => b - a).slice(0, use_limit)),
[]
)
.sort((a, b) => b - a)
.slice(0, num_wanted)
.reduce((ret, n) => ret + n, 0)
};
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#2 Code Example with Python Programming
Code -
Python Programming
class Solution:
def largestValsFromLabels(self, values: List[int], labels: List[int], num_wanted: int, use_limit: int) -> int:
cnt = collections.defaultdict(int)
heap = [[-a, b] for a, b in zip(values, labels)]
heapq.heapify(heap)
use = sm =0
while use < num_wanted and heap:
a, b = heapq.heappop(heap)
if cnt[b] < use_limit:
sm -= a
use += 1
cnt[b] += 1
return sm
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