Algorithm
Problem Name: 197. Rising Temperature
SQL Schema
Table: Weather
+---------------+---------+ | Column Name | Type | +---------------+---------+ | id | int | | recordDate | date | | temperature | int | +---------------+---------+ id is the primary key for this table. This table contains information about the temperature on a certain day.
Write an SQL query to find all dates' Id with higher temperatures compared to its previous dates (yesterday).
Return the result table in any order.
The query result format is in the following example.
Example 1:
Input: Weather table: +----+------------+-------------+ | id | recordDate | temperature | +----+------------+-------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +----+------------+-------------+ Output: +----+ | id | +----+ | 2 | | 4 | +----+ Explanation: In 2015-01-02, the temperature was higher than the previous day (10 -> 25). In 2015-01-04, the temperature was higher than the previous day (20 -> 30).
Code Examples
#1 Code Example with SQL
Code -
SQL
# Write your MySQL query statement below
SELECT Weather.Id
FROM Weather
JOIN Weather AS w
ON w.RecordDate = SUBDATE(Weather.RecordDate, 1)
WHERE Weather.Temperature > w.Temperature
Input
Weather table:
+----+------------+-------------+
| id | recordDate | temperature |
+----+------------+-------------+
| 1 | 2015-01-01 | 10 |
| 2 | 2015-01-02 | 25 |
| 3 | 2015-01-03 | 20 |
| 4 | 2015-01-04 | 30 |
+----+------------+-------------+
Output
+----+
| id |
+----+
| 2 |
| 4 |
+----+