## Algorithm

Problem Name: 1115. Print FooBar Alternately

Suppose you are given the following code:

```class FooBar {
public void foo() {
for (int i = 0; i < n; i++) {
print("foo");
}
}

public void bar() {
for (int i = 0; i < n; i++) {
print("bar");
}
}
}
```

The same instance of `FooBar` will be passed to two different threads:

• thread `A` will call `foo()`, while
• thread `B` will call `bar()`.

Modify the given program to output `"foobar"` `n` times.

Example 1:

```Input: n = 1
Output: "foobar"
Explanation: There are two threads being fired asynchronously. One of them calls foo(), while the other calls bar().
"foobar" is being output 1 time.
```

Example 2:

```Input: n = 2
Output: "foobarfoobar"
Explanation: "foobar" is being output 2 times.
```

Constraints:

• `1 <= n <= 1000`

## Code Examples

### #1 Code Example with Python Programming

```Code - Python Programming```

``````
class FooBar(object):
def __init__(self, n):
self.n = n
self.b.acquire()

def foo(self, printFoo):
"""
:type printFoo: method
:rtype: void
"""
for i in range(self.n):
self.f.acquire()
# printFoo() outputs "foo". Do not change or remove this line.
printFoo()
self.b.release()

def bar(self, printBar):
"""
:type printBar: method
:rtype: void
"""
for i in range(self.n):
self.b.acquire()
# printBar() outputs "bar". Do not change or remove this line.
printBar()
self.f.release()
``````
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