Algorithm


Problem Name: 561. Array Partition

Given an integer array nums of 2n integers, group these integers into n pairs (a1, b1), (a2, b2), ..., (an, bn) such that the sum of min(ai, bi) for all i is maximized. Return the maximized sum.

 

Example 1:

Input: nums = [1,4,3,2]
Output: 4
Explanation: All possible pairings (ignoring the ordering of elements) are:
1. (1, 4), (2, 3) -> min(1, 4) + min(2, 3) = 1 + 2 = 3
2. (1, 3), (2, 4) -> min(1, 3) + min(2, 4) = 1 + 2 = 3
3. (1, 2), (3, 4) -> min(1, 2) + min(3, 4) = 1 + 3 = 4
So the maximum possible sum is 4.

Example 2:

Input: nums = [6,2,6,5,1,2]
Output: 9
Explanation: The optimal pairing is (2, 1), (2, 5), (6, 6). min(2, 1) + min(2, 5) + min(6, 6) = 1 + 2 + 6 = 9.

 

Constraints:

  • 1 <= n <= 104
  • nums.length == 2 * n
  • -104 <= nums[i] <= 104
 

Code Examples

#1 Code Example with Python Programming

Code - Python Programming


class Solution:
    def arrayPairSum(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        nums.sort()
        sum=0
        while nums:
            num1=nums.pop()
            num2=nums.pop()
            sum+=num2
        return sum
            
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Input

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nums = [1,4,3,2]

Output

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4

#2 Code Example with C# Programming

Code - C# Programming


using System;

namespace LeetCode
{
    public class _0561_ArrayPartitionI
    {
        public int ArrayPairSum(int[] nums)
        {
            Array.Sort(nums);

            int sum = 0;
            for (var i = 0; i  <  nums.Length; i += 2)
                sum += nums[i];

            return sum;
        }
    }
}
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Input

x
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cmd
nums = [1,4,3,2]

Output

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4
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