Algorithm
Problem Name: 1221. Split a String in Balanced Strings
Balanced strings are those that have an equal quantity of 'L'
and 'R'
characters.
Given a balanced string s
, split it into some number of substrings such that:
- Each substring is balanced.
Return the maximum number of balanced strings you can obtain.
Example 1:
Input: s = "RLRRLLRLRL" Output: 4 Explanation: s can be split into "RL", "RRLL", "RL", "RL", each substring contains same number of 'L' and 'R'.
Example 2:
Input: s = "RLRRRLLRLL" Output: 2 Explanation: s can be split into "RL", "RRRLLRLL", each substring contains same number of 'L' and 'R'. Note that s cannot be split into "RL", "RR", "RL", "LR", "LL", because the 2nd and 5th substrings are not balanced.
Example 3:
Input: s = "LLLLRRRR" Output: 1 Explanation: s can be split into "LLLLRRRR".
Constraints:
2 <= s.length <= 1000
s[i]
is either'L'
or'R'
.s
is a balanced string.
Code Examples
#1 Code Example with Java Programming
Code -
Java Programming
class Solution {
public int balancedStringSplit(String s) {
int count = 0;
int val = 0;
for (char c : s.toCharArray()) {
val += c == 'L' ? -1 : 1;
if (val == 0) {
count++;
}
}
return count;
}
}
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#2 Code Example with Javascript Programming
Code -
Javascript Programming
const balancedStringSplit = function(s) {
let res = 0, num = 0
for(let ch of s) {
num += ch === 'L' ? 1 : -1
if(num === 0) res++
}
return res
};
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#3 Code Example with Python Programming
Code -
Python Programming
class Solution:
def balancedStringSplit(self, s: str) -> int:
res = cnt = 0
for c in s:
cnt += c == 'L'
cnt -= c == 'R'
res += cnt == 0
return res
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#4 Code Example with C# Programming
Code -
C# Programming
namespace LeetCode
{
public class _1221_SplitAStringInBalancedStrings
{
public int BalancedStringSplit(string s)
{
var count = 0;
var result = 0;
foreach (var ch in s)
{
count += ch == 'L' ? 1 : -1;
if (count == 0)
result++;
}
return result;
}
}
}
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