Algorithm
Problem Name: 746. Min Cost Climbing Stairs
You are given an integer array cost
where cost[i]
is the cost of ith
step on a staircase. Once you pay the cost, you can either climb one or two steps.
You can either start from the step with index 0
, or the step with index 1
.
Return the minimum cost to reach the top of the floor.
Example 1:
Input: cost = [10,15,20] Output: 15 Explanation: You will start at index 1. - Pay 15 and climb two steps to reach the top. The total cost is 15.
Example 2:
Input: cost = [1,100,1,1,1,100,1,1,100,1] Output: 6 Explanation: You will start at index 0. - Pay 1 and climb two steps to reach index 2. - Pay 1 and climb two steps to reach index 4. - Pay 1 and climb two steps to reach index 6. - Pay 1 and climb one step to reach index 7. - Pay 1 and climb two steps to reach index 9. - Pay 1 and climb one step to reach the top. The total cost is 6.
Constraints:
2 <= cost.length <= 1000
0 <= cost[i] <= 999
Code Examples
#1 Code Example with C++ Programming
Code -
C++ Programming
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#2 Code Example with Java Programming
Code -
Java Programming
class Solution {
public int minCostClimbingStairs(int[] cost) {
int n = cost.length;
int first = cost[0];
int second = cost[1];
for (int i = 2; i < n; i++) {
int curr = cost[i] + Math.min(first, second);
first = second;
second = curr;
}
return Math.min(first, second);
}
}
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#3 Code Example with Javascript Programming
Code -
Javascript Programming
const minCostClimbingStairs = function(cost) {
let f1 = cost[0];
let f2 = cost[1];
for (let i = 2; i < cost.length; i++) {
let f_cur = cost[i] + Math.min(f1, f2);
f1 = f2;
f2 = f_cur;
}
return Math.min(f1, f2);
};
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#4 Code Example with Python Programming
Code -
Python Programming
class Solution:
def minCostClimbingStairs(self, cost):
"""
:type cost: List[int]
:rtype: int
"""
for i in range(2,len(cost)): cost[i]+=min(cost[i-1],cost[i-2])
return min(cost[-1],cost[-2])
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#5 Code Example with C# Programming
Code -
C# Programming
using System;
namespace LeetCode
{
public class _0746_MinCostClimbingStairs
{
public int MinCostClimbingStairs(int[] cost)
{
int cost1 = 0, cost2 = 0;
var index = 2;
for (; index < cost.Length; index++)
{
var curr = Math.Min(cost1 + cost[index - 2], cost2 + cost[index - 1]);
cost1 = cost2;
cost2 = curr;
}
return Math.Min(cost1 + cost[index - 2], cost2 + cost[index - 1]);
}
}
}
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