Algorithm


Problem Name: 1094. Car Pooling

There is a car with capacity empty seats. The vehicle only drives east (i.e., it cannot turn around and drive west).

You are given the integer capacity and an array trips where trips[i] = [numPassengersi, fromi, toi] indicates that the ith trip has numPassengersi passengers and the locations to pick them up and drop them off are fromi and toi respectively. The locations are given as the number of kilometers due east from the car's initial location.

Return true if it is possible to pick up and drop off all passengers for all the given trips, or false otherwise.

 

Example 1:

Input: trips = [[2,1,5],[3,3,7]], capacity = 4
Output: false

Example 2:

Input: trips = [[2,1,5],[3,3,7]], capacity = 5
Output: true

 

Constraints:

  • 1 <= trips.length <= 1000
  • trips[i].length == 3
  • 1 <= numPassengersi <= 100
  • 0 <= fromi < toi <= 1000
  • 1 <= capacity <= 105

Code Examples

#1 Code Example with Java Programming

Code - Java Programming


class Solution {
  public boolean carPooling(int[][] trips, int capacity) {
    Arrays.sort(trips, Comparator.comparingInt(o -> o[1]));
    PriorityQueue < int[]> pq = new PriorityQueue<>(Comparator.comparingInt(a -> a[2]));
    for (int[] trip : trips) {
      while (!pq.isEmpty() && pq.peek()[2] <= trip[1]) {
        capacity += pq.poll()[0];
      }
      if (capacity  <  trip[0]) {
        return false;
      }
      pq.add(trip);
      capacity -= trip[0];
    }
    return true;
  }
}
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Input

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trips = [[2,1,5],[3,3,7]], capacity = 4

Output

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false

#2 Code Example with Javascript Programming

Code - Javascript Programming


const carPooling = function(trips, capacity) {
  const arr = Array(1001).fill(0)
  for(const [num, s, e] of trips) {
    arr[s] += num
    arr[e] -= num
  }
  for(let i = 1; i  <  1001; i++) {
    arr[i] += arr[i - 1]
  }
  
  for(let e of arr) {
    if(e > capacity) return false
  }
  return true
};
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Input

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trips = [[2,1,5],[3,3,7]], capacity = 4

Output

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false

#3 Code Example with Python Programming

Code - Python Programming


class Solution:
    def carPooling(self, trips: List[List[int]], capacity: int) -> bool:
        heap = []
        for a, b, c in trips:
            heapq.heappush(heap, (b, a))
            heapq.heappush(heap, (c, -a))
        cur = 0
        while heap:
            cur += heapq.heappop(heap)[1]
            if cur > capacity: return False
        return True
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Input

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trips = [[2,1,5],[3,3,7]], capacity = 5

Output

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true

#4 Code Example with C# Programming

Code - C# Programming


namespace LeetCode
{
    public class _1094_CarPooling
    {
        public bool CarPooling(int[][] trips, int capacity)
        {
            var timestamp = new int[1001];

            foreach (int[] trip in trips)
            {
                timestamp[trip[1]] += trip[0];
                timestamp[trip[2]] -= trip[0];
            }

            int ued_capacity = 0;
            foreach (int number in timestamp)
            {
                ued_capacity += number;
                if (ued_capacity > capacity)
                    return false;
            }
            return true;
        }
    }
}
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Input

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trips = [[2,1,5],[3,3,7]], capacity = 5

Output

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true
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