Algorithm
Problem Name: 1148. Article Views I
Problem Link: https://leetcode.com/problems/article-views-i/
SQL Schema
Table: Views
+---------------+---------+ | Column Name | Type | +---------------+---------+ | article_id | int | | author_id | int | | viewer_id | int | | view_date | date | +---------------+---------+ There is no primary key for this table, it may have duplicate rows. Each row of this table indicates that some viewer viewed an article (written by some author) on some date. Note that equal author_id and viewer_id indicate the same person.
Write an SQL query to find all the authors that viewed at least one of their own articles.
Return the result table sorted by id in ascending order.
The query result format is in the following example.
Example 1:
Input: Views table: +------------+-----------+-----------+------------+ | article_id | author_id | viewer_id | view_date | +------------+-----------+-----------+------------+ | 1 | 3 | 5 | 2019-08-01 | | 1 | 3 | 6 | 2019-08-02 | | 2 | 7 | 7 | 2019-08-01 | | 2 | 7 | 6 | 2019-08-02 | | 4 | 7 | 1 | 2019-07-22 | | 3 | 4 | 4 | 2019-07-21 | | 3 | 4 | 4 | 2019-07-21 | +------------+-----------+-----------+------------+ Output: +------+ | id | +------+ | 4 | | 7 | +------+
Code Examples
#1 Code Example with SQL
Code -
SQL
# Write your MySQL query statement below
SELECT DISTINCT author_id AS id FROM Views
where author_id = viewer_id
ORDER BY id;
Input
Views table:
+------------+-----------+-----------+------------+
| article_id | author_id | viewer_id | view_date |
+------------+-----------+-----------+------------+
| 1 | 3 | 5 | 2019-08-01 |
| 1 | 3 | 6 | 2019-08-02 |
| 2 | 7 | 7 | 2019-08-01 |
| 2 | 7 | 6 | 2019-08-02 |
| 4 | 7 | 1 | 2019-07-22 |
| 3 | 4 | 4 | 2019-07-21 |
| 3 | 4 | 4 | 2019-07-21 |
+------------+-----------+-----------+------------+
Output
+------+
| id |
+------+
| 4 |
| 7 |
+------+