## Algorithm

Problem Name: 1103. Distribute Candies to People

We distribute some number of `candies`, to a row of `n = num_people` people in the following way:

We then give 1 candy to the first person, 2 candies to the second person, and so on until we give `n` candies to the last person.

Then, we go back to the start of the row, giving `n + 1` candies to the first person, `n + 2` candies to the second person, and so on until we give `2 * n` candies to the last person.

This process repeats (with us giving one more candy each time, and moving to the start of the row after we reach the end) until we run out of candies.  The last person will receive all of our remaining candies (not necessarily one more than the previous gift).

Return an array (of length `num_people` and sum `candies`) that represents the final distribution of candies.

Example 1:

```Input: candies = 7, num_people = 4
Output: [1,2,3,1]
Explanation:
On the first turn, ans += 1, and the array is [1,0,0,0].
On the second turn, ans += 2, and the array is [1,2,0,0].
On the third turn, ans += 3, and the array is [1,2,3,0].
On the fourth turn, ans += 1 (because there is only one candy left), and the final array is [1,2,3,1].
```

Example 2:

```Input: candies = 10, num_people = 3
Output: [5,2,3]
Explanation:
On the first turn, ans += 1, and the array is [1,0,0].
On the second turn, ans += 2, and the array is [1,2,0].
On the third turn, ans += 3, and the array is [1,2,3].
On the fourth turn, ans += 4, and the final array is [5,2,3].
```

Constraints:

• 1 <= candies <= 10^9
• 1 <= num_people <= 1000

## Code Examples

### #1 Code Example with Java Programming

```Code - Java Programming```

``````
class Solution {
public int[] distributeCandies(int candies, int num_people) {
int[] people = new int[num_people];
for (int give = 0; candies > 0; candies -= give) {
people[give % num_people] +=  Math.min(candies, ++give);
}
return people;
}
}
``````
Copy The Code &

Input

cmd
candies = 7, num_people = 4

Output

cmd
[1,2,3,1]

### #2 Code Example with Javascript Programming

```Code - Javascript Programming```

``````
const distributeCandies = function(candies, num_people) {
const n = num_people
const res = Array(n).fill(0)
let idx = 0, cur = 0
while(candies > 0) {
cur++
res[idx] += Math.min(cur, candies)
idx++
candies -= cur
if(idx === n) idx = 0
}
return res
};
``````
Copy The Code &

Input

cmd
candies = 7, num_people = 4

Output

cmd
[1,2,3,1]

### #3 Code Example with Python Programming

```Code - Python Programming```

``````
class Solution:
def distributeCandies(self, candies: int, num_people: int) -> List[int]:
res =  * num_people
i = 0
while candies > 0:
res[i % num_people] += min(candies, i + 1)
i += 1
candies -= i
return res
``````
Copy The Code &

Input

cmd
candies = 10, num_people = 3

Output

cmd
[5,2,3]

### #4 Code Example with C# Programming

```Code - C# Programming```

``````
using System;

namespace LeetCode
{
public class _1103_DistributeCandiesToPeople
{
public int[] DistributeCandies(int candies, int num_people)
{
int people = (int)(Math.Sqrt(2 * candies + 0.25) - 0.5);
int remaining = candies - (people + 1) * people / 2;
int rows = people / num_people, cols = people % num_people;

var result = new int[num_people];
for (int i = 0; i < num_people; i++)
{
result[i] = (i + 1) * rows + (rows * (rows - 1) / 2) * num_people;
if (i < cols)
result[i] += i + 1 + rows * num_people;
}
result[cols] += remaining;
return result;
}
}
}
``````
Copy The Code &

Input

cmd
candies = 10, num_people = 3

Output

cmd
[5,2,3]