Algorithm


Problem Name: 330. Patching Array

Problem Link: https://leetcode.com/problems/patching-array/
 

Given a sorted integer array nums and an integer n, add/patch elements to the array such that any number in the range [1, n] inclusive can be formed by the sum of some elements in the array.

Return the minimum number of patches required.

 

Example 1:

Input: nums = [1,3], n = 6
Output: 1
Explanation:
Combinations of nums are [1], [3], [1,3], which form possible sums of: 1, 3, 4.
Now if we add/patch 2 to nums, the combinations are: [1], [2], [3], [1,3], [2,3], [1,2,3].
Possible sums are 1, 2, 3, 4, 5, 6, which now covers the range [1, 6].
So we only need 1 patch.

Example 2:

Input: nums = [1,5,10], n = 20
Output: 2
Explanation: The two patches can be [2, 4].

Example 3:

Input: nums = [1,2,2], n = 5
Output: 0

 

Constraints:

  • 1 <= nums.length <= 1000
  • 1 <= nums[i] <= 104
  • nums is sorted in ascending order.
  • 1 <= n <= 231 - 1

Code Examples

#1 Code Example with Javascript Programming

Code - Javascript Programming


const minPatches = function(nums, n) {
  let answer = 0
  for (let i = 0, next = 1; next  < = n; ) {
    if (i >= nums.length || nums[i] > next) {
      answer++
      next *= 2
    } else next += nums[i++]
  }
  return answer
}
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Input

x
+
cmd
nums = [1,3], n = 6

Output

x
+
cmd
1

#2 Code Example with Python Programming

Code - Python Programming


class Solution:
    def minPatches(self, nums, n):
        miss, added, i = 1, 0, 0
        while miss <= n:
            if i < len(nums) and nums[i] <= miss:
                miss += nums[i]
                i += 1
            else:
                miss *= 2
                added += 1
        return added
Copy The Code & Try With Live Editor

Input

x
+
cmd
nums = [1,3], n = 6

Output

x
+
cmd
1
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