Algorithm
Problem Name: 627. Swap Salary
Problem Link: https://leetcode.com/problems/swap-salary/
SQL Schema
Table: Salary
+-------------+----------+
| Column Name | Type |
+-------------+----------+
| id | int |
| name | varchar |
| sex | ENUM |
| salary | int |
+-------------+----------+
id is the primary key for this table.
The sex column is ENUM value of type ('m', 'f').
The table contains information about an employee.
Write an SQL query to swap all 'f' and 'm' values (i.e., change all 'f' values to 'm' and vice versa) with a single update statement and no intermediate temporary tables.
Note that you must write a single update statement, do not write any select statement for this problem.
The query result format is in the following example.
Example 1:
Input: Salary table: +----+------+-----+--------+ | id | name | sex | salary | +----+------+-----+--------+ | 1 | A | m | 2500 | | 2 | B | f | 1500 | | 3 | C | m | 5500 | | 4 | D | f | 500 | +----+------+-----+--------+ Output: +----+------+-----+--------+ | id | name | sex | salary | +----+------+-----+--------+ | 1 | A | f | 2500 | | 2 | B | m | 1500 | | 3 | C | f | 5500 | | 4 | D | m | 500 | +----+------+-----+--------+ Explanation: (1, A) and (3, C) were changed from 'm' to 'f'. (2, B) and (4, D) were changed from 'f' to 'm'.
Code Examples
#1 Code Example with SQL
Code -
SQL
# Write your MySQL query statement below
UPDATE salary SET sex = IF(sex='m','f','m');
Input
Salary table:
+----+------+-----+--------+
| id | name | sex | salary |
+----+------+-----+--------+
| 1 | A | m | 2500 |
| 2 | B | f | 1500 |
| 3 | C | m | 5500 |
| 4 | D | f | 500 |
+----+------+-----+--------+
Output
+----+------+-----+--------+
| id | name | sex | salary |
+----+------+-----+--------+
| 1 | A | f | 2500 |
| 2 | B | m | 1500 |
| 3 | C | f | 5500 |
| 4 | D | m | 500 |
+----+------+-----+--------+