Algorithm


Problem Name: 133. Clone Graph

Given a reference of a node in a connected undirected graph.

Return a deep copy (clone) of the graph.

Each node in the graph contains a value (int) and a list (List[Node]) of its neighbors.

class Node {
    public int val;
    public List<Node> neighbors;
}

 

Test case format:

For simplicity, each node's value is the same as the node's index (1-indexed). For example, the first node with val == 1, the second node with val == 2, and so on. The graph is represented in the test case using an adjacency list.

An adjacency list is a collection of unordered lists used to represent a finite graph. Each list describes the set of neighbors of a node in the graph.

The given node will always be the first node with val = 1. You must return the copy of the given node as a reference to the cloned graph.

 

Example 1:

Input: adjList = [[2,4],[1,3],[2,4],[1,3]]
Output: [[2,4],[1,3],[2,4],[1,3]]
Explanation: There are 4 nodes in the graph.
1st node (val = 1)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
2nd node (val = 2)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).
3rd node (val = 3)'s neighbors are 2nd node (val = 2) and 4th node (val = 4).
4th node (val = 4)'s neighbors are 1st node (val = 1) and 3rd node (val = 3).

Example 2:

Input: adjList = [[]]
Output: [[]]
Explanation: Note that the input contains one empty list. The graph consists of only one node with val = 1 and it does not have any neighbors.

Example 3:

Input: adjList = []
Output: []
Explanation: This an empty graph, it does not have any nodes.

 

Constraints:

  • The number of nodes in the graph is in the range [0, 100].
  • 1 <= Node.val <= 100
  • Node.val is unique for each node.
  • There are no repeated edges and no self-loops in the graph.
  • The Graph is connected and all nodes can be visited starting from the given node.

Code Examples

#1 Code Example with C Programming

Code - C Programming

start coding...
struct UndirectedGraphNode *copy1node(struct UndirectedGraphNode *graph, 
                                      struct UndirectedGraphNode ***srcpool, 
                                      struct UndirectedGraphNode ***dstpool, 
                                      int *sp, int *sz) {
    struct UndirectedGraphNode *node;
    int i = 0;
    
    if (!graph) return NULL;
    
    while (i  <  *sp && (*srcpool)[i] != graph) {
        i ++;
    }
    if (i == *sp) {
        node = malloc(sizeof(struct UndirectedGraphNode));
        //assert(node);
        node->label = graph->label;
        if (*sp == *sz) {
            *sz = *sz * 2;
            *srcpool = realloc(*srcpool, *sz * sizeof(struct UndirectedGraphNode *));
            *dstpool = realloc(*dstpool, *sz * sizeof(struct UndirectedGraphNode *));
            //assert(*srcpool && *dstpool && *stspool);
        }
        (*srcpool)[*sp] = graph;
        (*dstpool)[*sp] = node;
        (*sp) += 1;
        i = 0;
        while (i  <  graph->neighborsCount) {
            node->neighbors[i] = copy1node(graph->neighbors[i], srcpool, dstpool, sp, sz);
            i ++;
        }
        node->neighborsCount = graph->neighborsCount;
    } else {
        node = (*dstpool)[i];
    }
    
    return node;
}

struct UndirectedGraphNode *cloneGraph(struct UndirectedGraphNode *graph) {
    struct UndirectedGraphNode **srcpool, **dstpool, *node;
    int sp = 0, sz = 100;
    
    srcpool = malloc(sz * sizeof(struct UndirectedGraphNode *));
    dstpool = malloc(sz * sizeof(struct UndirectedGraphNode *));
    //assert(srcpool && dstpool && stspool);
    
    node = copy1node(graph, &srcpool, &dstpool, &sp, &sz);
    
    free(srcpool); free(dstpool);
    
    return node;
}
Copy The Code & Try With Live Editor

Input

x
+
cmd
adjList = [[2,4],[1,3],[2,4],[1,3]]

Output

x
+
cmd
[[2,4],[1,3],[2,4],[1,3]]

#2 Code Example with C++ Programming

Code - C++ Programming

class Solution {
private:
    unordered_mapm;
public:
    UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
        if(!node) return NULL;
        if(m.count(node) == 0){
            m[node] = new UndirectedGraphNode(node->label);
            for(auto x: node->neighbors) m[node]->neighbors.push_back(cloneGraph(x));
        }
        return m[node];
    }
};

// BFS
class Solution {
public:
    UndirectedGraphNode *cloneGraph(UndirectedGraphNode *node) {
        if(!node) return NULL;
        unordered_map < UndirectedGraphNode*, UndirectedGraphNode*>m;
        UndirectedGraphNode* root = new UndirectedGraphNode(node->label);
        m[node] = root;
        deque < UndirectedGraphNode*>cur;
        dequenext;
        cur.push_back(node);
        while(!cur.empty()){
            UndirectedGraphNode* p = cur.front();
            cur.pop_front();
            for(auto x: p->neighbors){
                if(m.count(x) == 0){
                    UndirectedGraphNode* copy = new UndirectedGraphNode(x->label);
                    m[x] = copy;
                    next.push_back(x);
                }
                m[p]->neighbors.push_back(m[x]);
            }
            if(cur.empty()) swap(cur, next);
        }
        return root;
    }
};

Copy The Code & Try With Live Editor

Input

x
+
cmd
adjList = [[2,4],[1,3],[2,4],[1,3]]

Output

x
+
cmd
[[2,4],[1,3],[2,4],[1,3]]

#3 Code Example with Java Programming

Code - Java Programming


class Solution {
  public Node cloneGraph(Node node) {
    if (node == null) {
      return null;
    }
    Map < Node, Node> map = new HashMap<>();
    Queue queue = new LinkedList<>();
    queue.add(node);
    map.put(node, new Node(node.val));
    while (!queue.isEmpty()) {
      Node removed = queue.remove();
      for (Node neighbor : removed.neighbors) {
        if (!map.containsKey(neighbor)) {
          map.put(neighbor, new Node(neighbor.val));
          queue.add(neighbor);
        }
        map.get(removed).neighbors.add(map.get(neighbor));
      }
    }
    return map.get(node);
  }
}
Copy The Code & Try With Live Editor

Input

x
+
cmd
adjList = [[]]

Output

x
+
cmd
[[]]

#4 Code Example with Javascript Programming

Code - Javascript Programming


const cloneGraph = function(node) {
  if (!node) return node
  const map = {}
  return traverse(node)
  function traverse(node) {
    if(!node) return node;
    if (!map[node.val]) {
      const newNode = new Node(node.val)
      map[node.val] = newNode
      newNode.neighbors = node.neighbors.map(traverse)
    }
    return map[node.val]
  }
}
Copy The Code & Try With Live Editor

Input

x
+
cmd
adjList = [[]]

Output

x
+
cmd
[[]]

#5 Code Example with Python Programming

Code - Python Programming


class Solution:
    def cloneGraph(self, node: "Node") -> "Node":
        visited = {}

        def dfs(node):
            if node and node.val not in visited:
                newNode = Node(node.val, [])
                visited[newNode.val] = newNode
                newNode.neighbors = [
                    visited.get(n.val) or dfs(n) for n in node.neighbors
                ]
                return newNode

        return dfs(node)
Copy The Code & Try With Live Editor

Input

x
+
cmd
adjList = []

Output

x
+
cmd
[]

#6 Code Example with C# Programming

Code - C# Programming


using System.Collections.Generic;

namespace LeetCode
{
    public class _0133_CloneGraph
    {
        public Node CloneGraph(Node node)
        {
            var map = new Dictionary < int, Node>();
            return CloneGraph(node, map);
        }

        public Node CloneGraph(Node node, IDictionary < int, Node> map)
        {
            if (node == null) return null;
            if (map.ContainsKey(node.val)) return map[node.val];

            var newNode = new Node(node.val, new List < Node>());
            map.Add(node.val, newNode);
            foreach (var child in node.neighbors)
                newNode.neighbors.Add(CloneGraph(child, map));

            return newNode;
        }

        public class Node
        {
            public int val;
            public IList < Node> neighbors;

            public Node() { }

            public Node(int _val, IList _neighbors)
            {
                val = _val;
                neighbors = _neighbors;
            }
        }
    }
}
Copy The Code & Try With Live Editor

Input

x
+
cmd
adjList = []

Output

x
+
cmd
[]
Advertisements

Demonstration


Previous
#132 Leetcode Palindrome Partitioning II Solution in C, C++, Java, JavaScript, Python, C# Leetcode
Next
#134 Leetcode Gas Station Solution in C, C++, Java, JavaScript, Python, C# Leetcode