Algorithm


Problem Name: 559. Maximum Depth of N-ary Tree

Given a n-ary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).

 

Example 1:

Input: root = [1,null,3,2,4,null,5,6]
Output: 3

Example 2:

Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]
Output: 5

 

Constraints:

  • The total number of nodes is in the range [0, 104].
  • The depth of the n-ary tree is less than or equal to 1000.

Code Examples

#1 Code Example with Java Programming

Code - Java Programming


class Solution {
    public int maxDepth(Node root) {
        if (root == null) {
            return 0;
        }
        
        int max = Integer.MIN_VALUE;
        
        for (Node child : root.children) {
            max = Math.max(max, maxDepth(child));
        }
        
        return 1 + Math.max(max, 0);
    }
}
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Input

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root = [1,null,3,2,4,null,5,6]

Output

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3

#2 Code Example with Javascript Programming

Code - Javascript Programming


const maxDepth = function(root) {
  let max = 0
  if(root == null) return 0
  function dfs(node, depth) {
    if(node == null || node.children.length === 0) {
      depth++
      if(depth > max) max = depth
      return
    }
    depth++
    for(let n of node.children) {
      dfs(n, depth)
    }
  }
  dfs(root, 0)
  return max
};
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Input

x
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cmd
root = [1,null,3,2,4,null,5,6]

Output

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3

#3 Code Example with C# Programming

Code - C# Programming


using System;
using System.Collections.Generic;

namespace LeetCode
{
    public class _0559_MaximumDepthOfNAryTree
    {
        public int MaxDepth(Node root)
        {
            if (root == null) return 0;

            var max = 0;
            foreach (var child in root.children)
                max = Math.Max(max, MaxDepth(child));

            return max + 1;
        }

        public class Node
        {
            public int val;
            public IList < Node> children;

            public Node() { }

            public Node(int _val)
            {
                val = _val;
                children = new List < Node>();
            }

            public Node(int _val, IList _children)
            {
                val = _val;
                children = _children;
            }
        }
    }
}
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Input

x
+
cmd
root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14]

Output

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5
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